What are the solutions to the equation completesquare x^2+x-56=0 ?

The solutions to the equation completesquare x^2+x-56=0 are x=7,x=-8

Find the zeros of completesquare x^2+x-56=0

The zeros of completesquare x^2+x-56=0 are x=7,x=-8

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x^{2} + x - 56 = 0

x = 7, x = - 8

Solution steps

x^{2} + x - 56 = 0

Move

56

to the right side

x^{2} + x = 56

Rewrite in the form

(x + a)^{2} = b

(x + \frac{1}{2})^{2} = \frac{225}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{1}{2} = \frac{225}{4} : x = 7

Solve

x + \frac{1}{2} = - \frac{225}{4} : x = - 8

The solutions to the quadratic equation are:

x = 7, x = - 8

z, x^{2} + y^{2} = z^{2}

(r^{2} + r + 1) = 0

10 p^{2} + 2.5 (1 - p^{2}) = 2.5 p^{2} + 5 (1 - p^{2})

x, x^{2} + 16 = 0

p^{2} + p - 42 = 0

What are the solutions to the equation completesquare x^2+x-56=0 ?
The solutions to the equation completesquare x^2+x-56=0 are x=7,x=-8
Find the zeros of completesquare x^2+x-56=0
The zeros of completesquare x^2+x-56=0 are x=7,x=-8