What are the solutions to the equation (r^2+r+1)=0 ?

The solutions to the equation (r^2+r+1)=0 are r=-1/2+i(sqrt(3))/2 ,r=-1/2-i(sqrt(3))/2

Find the zeros of (r^2+r+1)=0

The zeros of (r^2+r+1)=0 are r=-1/2+i(sqrt(3))/2 ,r=-1/2-i(sqrt(3))/2

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(r^{2} + r + 1) = 0

r = - \frac{1}{2} + i \frac{3}{2}, r = - \frac{1}{2} - i \frac{3}{2}

Solution steps

(r^{2} + r + 1) = 0

Refine

r^{2} + r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 1 : 3 i

r_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, r_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

r = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

r = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

r = - \frac{1}{2} + i \frac{3}{2}, r = - \frac{1}{2} - i \frac{3}{2}

10 p^{2} + 2.5 (1 - p^{2}) = 2.5 p^{2} + 5 (1 - p^{2})

x, x^{2} + 16 = 0

p^{2} + p - 42 = 0

(- x^{2} - 1) = 0

9 x^{2} - 6 x + 2

What are the solutions to the equation (r^2+r+1)=0 ?
The solutions to the equation (r^2+r+1)=0 are r=-1/2+i(sqrt(3))/2 ,r=-1/2-i(sqrt(3))/2
Find the zeros of (r^2+r+1)=0
The zeros of (r^2+r+1)=0 are r=-1/2+i(sqrt(3))/2 ,r=-1/2-i(sqrt(3))/2