What are the solutions to the equation 2x^2-5=67 ?

The solutions to the equation 2x^2-5=67 are x=6,x=-6

Find the zeros of 2x^2-5=67

The zeros of 2x^2-5=67 are x=6,x=-6

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2 x^{2} - 5 = 67

x = 6, x = - 6

Solution steps

2 x^{2} - 5 = 67

Move

5

to the right side

2 x^{2} = 72

Divide both sides by

2

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

\frac{q ^{2}}{10000} - q + 3900 = 7000 - 1.1 q

x, x^{2} + 5 x - (p^{2} + p - 6) = 0

- 17 - 8 x^{2} = 4 x - 3 x^{2}

- x^{2} - 9 x + 22 = 0

- 0.2 (q - 25)^{2} + 165 = - 2 q + 140

What are the solutions to the equation 2x^2-5=67 ?
The solutions to the equation 2x^2-5=67 are x=6,x=-6
Find the zeros of 2x^2-5=67
The zeros of 2x^2-5=67 are x=6,x=-6