What are the solutions to the equation x^2+4x-72=0 ?

The solutions to the equation x^2+4x-72=0 are x=2(sqrt(19)-1),x=-2(1+sqrt(19))

Find the zeros of x^2+4x-72=0

The zeros of x^2+4x-72=0 are x=2(sqrt(19)-1),x=-2(1+sqrt(19))

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x^{2} + 4 x - 72 = 0

x = 2 (19 - 1), x = - 2 (1 + 19)

Decimal Notation

x = 6.71779 \dots, x = - 10.71779 \dots

Solution steps

x^{2} + 4 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 72) = 419

x_{1, 2} = \frac{- 4 \pm 4 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 19}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 19}{2 \cdot 1}

x = \frac{- 4 + 4 19}{2 \cdot 1} : 2 (19 - 1)

x = \frac{- 4 - 4 19}{2 \cdot 1} : - 2 (1 + 19)

The solutions to the quadratic equation are:

x = 2 (19 - 1), x = - 2 (1 + 19)

x^{2} - \frac{1}{3} x - \frac{4}{9} = 0

16 x^{2} - 24 x + 5 = 0

2 x^{(2)} + 5 x - 2 = 0

x, s (x) = - 2 x^{2} - 12 x - 17

10 - 6 (8 x - 2) = 9 x (3 + 4 x)

What are the solutions to the equation x^2+4x-72=0 ?
The solutions to the equation x^2+4x-72=0 are x=2(sqrt(19)-1),x=-2(1+sqrt(19))
Find the zeros of x^2+4x-72=0
The zeros of x^2+4x-72=0 are x=2(sqrt(19)-1),x=-2(1+sqrt(19))