What are the solutions to the equation x^2-1/3 x-4/9 =0 ?

The solutions to the equation x^2-1/3 x-4/9 =0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6

Find the zeros of x^2-1/3 x-4/9 =0

The zeros of x^2-1/3 x-4/9 =0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6

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x^{2} - \frac{1}{3} x - \frac{4}{9} = 0

x = \frac{1 + 17}{6}, x = \frac{1 - 17}{6}

Decimal Notation

x = 0.85385 \dots, x = - 0.52051 \dots

Solution steps

x^{2} - \frac{1}{3} x - \frac{4}{9} = 0

Find Least Common Multiplier of

3, 9 : 9

Multiply by LCM=

9

x^{2} \cdot 9 - \frac{1}{3} x \cdot 9 - \frac{4}{9} \cdot 9 = 0 \cdot 9

Simplify

9 x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 4) = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 \cdot 9}

x = \frac{- ( - 3 ) + 3 17}{2 \cdot 9} : \frac{1 + 17}{6}

x = \frac{- ( - 3 ) - 3 17}{2 \cdot 9} : \frac{1 - 17}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 17}{6}, x = \frac{1 - 17}{6}

16 x^{2} - 24 x + 5 = 0

2 x^{(2)} + 5 x - 2 = 0

x, s (x) = - 2 x^{2} - 12 x - 17

10 - 6 (8 x - 2) = 9 x (3 + 4 x)

x, x^{2} + y^{2} + z^{6} = 1

What are the solutions to the equation x^2-1/3 x-4/9 =0 ?
The solutions to the equation x^2-1/3 x-4/9 =0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6
Find the zeros of x^2-1/3 x-4/9 =0
The zeros of x^2-1/3 x-4/9 =0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6