What are the solutions to the equation 16x^2-24x+5=0 ?

The solutions to the equation 16x^2-24x+5=0 are x= 5/4 ,x= 1/4

Find the zeros of 16x^2-24x+5=0

The zeros of 16x^2-24x+5=0 are x= 5/4 ,x= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} - 24 x + 5 = 0

x = \frac{5}{4}, x = \frac{1}{4}

Decimal

x = 1.25, x = 0.25

Solution steps

16 x^{2} - 24 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 5}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 5 = 16

x_{1, 2} = \frac{- ( - 24 ) \pm 16}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 16}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 16}{2 \cdot 16}

x = \frac{- ( - 24 ) + 16}{2 \cdot 16} : \frac{5}{4}

x = \frac{- ( - 24 ) - 16}{2 \cdot 16} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{1}{4}

2 x^{(2)} + 5 x - 2 = 0

x, s (x) = - 2 x^{2} - 12 x - 17

10 - 6 (8 x - 2) = 9 x (3 + 4 x)

x, x^{2} + y^{2} + z^{6} = 1

(x - 1)^{2} = 3 x - 5

What are the solutions to the equation 16x^2-24x+5=0 ?
The solutions to the equation 16x^2-24x+5=0 are x= 5/4 ,x= 1/4
Find the zeros of 16x^2-24x+5=0
The zeros of 16x^2-24x+5=0 are x= 5/4 ,x= 1/4