What are the solutions to the equation 3-x^2=1-x ?

The solutions to the equation 3-x^2=1-x are x=-1,x=2

Find the zeros of 3-x^2=1-x

The zeros of 3-x^2=1-x are x=-1,x=2

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3 - x^{2} = 1 - x

x = - 1, x = 2

Solution steps

3 - x^{2} = 1 - x

Move

x

to the left side

3 - x^{2} + x = 1

Move

1

to the left side

- x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 ( - 1 )}, x_{2} = \frac{- 1 - 3}{2 ( - 1 )}

x = \frac{- 1 + 3}{2 ( - 1 )} : - 1

x = \frac{- 1 - 3}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

2 x^{2} + 8 x - 11 = 0

\frac{1}{3} (u - \frac{3}{2}) (u + \frac{3}{2}) = u (\frac{u}{3} \frac{1}{4})

2 x^{2} - 10 x = 0

x - 3 - (- x (x + 1) + 4) - 5 = (- x + 6)

2 x^{2} - 378.4 x + 17856 = 0

What are the solutions to the equation 3-x^2=1-x ?
The solutions to the equation 3-x^2=1-x are x=-1,x=2
Find the zeros of 3-x^2=1-x
The zeros of 3-x^2=1-x are x=-1,x=2