What are the solutions to the equation x^2+200x+100000=0 ?

The solutions to the equation x^2+200x+100000=0 are x=-100+300i,x=-100-300i

Find the zeros of x^2+200x+100000=0

The zeros of x^2+200x+100000=0 are x=-100+300i,x=-100-300i

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x^{2} + 200 x + 100000 = 0

x = - 100 + 300 i, x = - 100 - 300 i

Solution steps

x^{2} + 200 x + 100000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 \cdot 1 \cdot 100000}{2 \cdot 1}

Simplify

20 0^{2} - 4 \cdot 1 \cdot 100000 : 600 i

x_{1, 2} = \frac{- 200 \pm 600 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 200 + 600 i}{2 \cdot 1}, x_{2} = \frac{- 200 - 600 i}{2 \cdot 1}

x = \frac{- 200 + 600 i}{2 \cdot 1} : - 100 + 300 i

x = \frac{- 200 - 600 i}{2 \cdot 1} : - 100 - 300 i

The solutions to the quadratic equation are:

x = - 100 + 300 i, x = - 100 - 300 i

3 x^{2} - 21 x + 27 = 0

(x + 2) (x - 1) = 5

(16 - 2 x) (9 - 2 x) = 78

x^{2} + m = (m + 1) x - 1

0 = x^{2} + 5 x + 2

What are the solutions to the equation x^2+200x+100000=0 ?
The solutions to the equation x^2+200x+100000=0 are x=-100+300i,x=-100-300i
Find the zeros of x^2+200x+100000=0
The zeros of x^2+200x+100000=0 are x=-100+300i,x=-100-300i