What are the solutions to the equation n^2-2n+18=3 ?

The solutions to the equation n^2-2n+18=3 are n=1+sqrt(14)i,n=1-sqrt(14)i

Find the zeros of n^2-2n+18=3

The zeros of n^2-2n+18=3 are n=1+sqrt(14)i,n=1-sqrt(14)i

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n^{2} - 2 n + 18 = 3

n = 1 + 14 i, n = 1 - 14 i

Solution steps

n^{2} - 2 n + 18 = 3

Move

3

to the left side

n^{2} - 2 n + 15 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 15 : 214 i

n_{1, 2} = \frac{- ( - 2 ) \pm 2 14 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 1}, n_{2} = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 1}

n = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 1} : 1 + 14 i

n = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 1} : 1 - 14 i

The solutions to the quadratic equation are:

n = 1 + 14 i, n = 1 - 14 i

3 x^{2} + 6 = 10

6 x^{2} + (\frac{5}{2}) x + \frac{1}{4} = 0

6 x^{2} - 3500 x + 25 \cdot 1 0^{4} = 0

3 m^{2} - 2 = 7

y^{2} - 6 y + 1 = - y^{2} + 2 y + 1

What are the solutions to the equation n^2-2n+18=3 ?
The solutions to the equation n^2-2n+18=3 are n=1+sqrt(14)i,n=1-sqrt(14)i
Find the zeros of n^2-2n+18=3
The zeros of n^2-2n+18=3 are n=1+sqrt(14)i,n=1-sqrt(14)i