What are the solutions to the equation 6x^2-3500x+25*10^4=0 ?

The solutions to the equation 6x^2-3500x+25*10^4=0 are x=500,x= 250/3

Find the zeros of 6x^2-3500x+25*10^4=0

The zeros of 6x^2-3500x+25*10^4=0 are x=500,x= 250/3

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6 x^{2} - 3500 x + 25 \cdot 1 0^{4} = 0

x = 500, x = \frac{250}{3}

Decimal Notation

x = 500, x = 83.33333 \dots

Solution steps

6 x^{2} - 3500 x + 25 \cdot 1 0^{4} = 0

Expand

6 x^{2} - 3500 x + 25 \cdot 1 0^{4} : 6 x^{2} - 3500 x + 250000

6 x^{2} - 3500 x + 250000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3500 ) \pm ( - 3500 ) ^{2} - 4 \cdot 6 \cdot 250000}{2 \cdot 6}

(- 3500)^{2} - 4 \cdot 6 \cdot 250000 = 2500

x_{1, 2} = \frac{- ( - 3500 ) \pm 2500}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 3500 ) + 2500}{2 \cdot 6}, x_{2} = \frac{- ( - 3500 ) - 2500}{2 \cdot 6}

x = \frac{- ( - 3500 ) + 2500}{2 \cdot 6} : 500

x = \frac{- ( - 3500 ) - 2500}{2 \cdot 6} : \frac{250}{3}

The solutions to the quadratic equation are:

x = 500, x = \frac{250}{3}

3 m^{2} - 2 = 7

y^{2} - 6 y + 1 = - y^{2} + 2 y + 1

0 = x^{2} + 10 x

x^{2} + (\frac{48}{7})^{2} = 1

x, 3 x^{2} - 2 x y + 3 y^{2} - 4 x - 4 y - 12 = 0

What are the solutions to the equation 6x^2-3500x+25*10^4=0 ?
The solutions to the equation 6x^2-3500x+25*10^4=0 are x=500,x= 250/3
Find the zeros of 6x^2-3500x+25*10^4=0
The zeros of 6x^2-3500x+25*10^4=0 are x=500,x= 250/3