What are the solutions to the equation 10x^2+22x+4=0 ?

The solutions to the equation 10x^2+22x+4=0 are x=-1/5 ,x=-2

Find the zeros of 10x^2+22x+4=0

The zeros of 10x^2+22x+4=0 are x=-1/5 ,x=-2

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10 x^{2} + 22 x + 4 = 0

x = - \frac{1}{5}, x = - 2

Decimal Notation

x = - 0.2, x = - 2

Solution steps

10 x^{2} + 22 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 10 \cdot 4}{2 \cdot 10}

2 2^{2} - 4 \cdot 10 \cdot 4 = 18

x_{1, 2} = \frac{- 22 \pm 18}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 22 + 18}{2 \cdot 10}, x_{2} = \frac{- 22 - 18}{2 \cdot 10}

x = \frac{- 22 + 18}{2 \cdot 10} : - \frac{1}{5}

x = \frac{- 22 - 18}{2 \cdot 10} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 2

a, b^{3} - 3 a b^{2} - 2 a^{2} b = o

x^{2} - 3 x = 0

- 4 x^{2} - 16 x - 19 = 0

y, x = 9 - y^{2}

t, h = - 16 t^{2} + 50

What are the solutions to the equation 10x^2+22x+4=0 ?
The solutions to the equation 10x^2+22x+4=0 are x=-1/5 ,x=-2
Find the zeros of 10x^2+22x+4=0
The zeros of 10x^2+22x+4=0 are x=-1/5 ,x=-2