What are the solutions to the equation 2x^2+8x-34=0 ?

The solutions to the equation 2x^2+8x-34=0 are x=-2+sqrt(21),x=-2-sqrt(21)

Find the zeros of 2x^2+8x-34=0

The zeros of 2x^2+8x-34=0 are x=-2+sqrt(21),x=-2-sqrt(21)

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2 x^{2} + 8 x - 34 = 0

x = - 2 + 21, x = - 2 - 21

Decimal Notation

x = 2.58257 \dots, x = - 6.58257 \dots

Solution steps

2 x^{2} + 8 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 34 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 34) = 421

x_{1, 2} = \frac{- 8 \pm 4 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 21}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 21}{2 \cdot 2}

x = \frac{- 8 + 4 21}{2 \cdot 2} : - 2 + 21

x = \frac{- 8 - 4 21}{2 \cdot 2} : - 2 - 21

The solutions to the quadratic equation are:

x = - 2 + 21, x = - 2 - 21

3 x^{2} + 4 x = - 1

- 6 x^{2} + 2 = 0

3 x^{2} + x - 102 = 0

1 - x^{2}

x^{2} - 2 x + 50

What are the solutions to the equation 2x^2+8x-34=0 ?
The solutions to the equation 2x^2+8x-34=0 are x=-2+sqrt(21),x=-2-sqrt(21)
Find the zeros of 2x^2+8x-34=0
The zeros of 2x^2+8x-34=0 are x=-2+sqrt(21),x=-2-sqrt(21)