What are the solutions to the equation 3x^2+63x+12=39 ?

The solutions to the equation 3x^2+63x+12=39 are x=(3(sqrt(53)-7))/2 ,x=-(3(7+sqrt(53)))/2

Find the zeros of 3x^2+63x+12=39

The zeros of 3x^2+63x+12=39 are x=(3(sqrt(53)-7))/2 ,x=-(3(7+sqrt(53)))/2

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3 x^{2} + 63 x + 12 = 39

x = \frac{3 ( 53 - 7 )}{2}, x = - \frac{3 ( 7 + 53 )}{2}

Decimal Notation

x = 0.42016 \dots, x = - 21.42016 \dots

Solution steps

3 x^{2} + 63 x + 12 = 39

Move

39

to the left side

3 x^{2} + 63 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 63 \pm 6 3 ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

6 3^{2} - 4 \cdot 3 (- 27) = 953

x_{1, 2} = \frac{- 63 \pm 9 53}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 63 + 9 53}{2 \cdot 3}, x_{2} = \frac{- 63 - 9 53}{2 \cdot 3}

x = \frac{- 63 + 9 53}{2 \cdot 3} : \frac{3 ( 53 - 7 )}{2}

x = \frac{- 63 - 9 53}{2 \cdot 3} : - \frac{3 ( 7 + 53 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 53 - 7 )}{2}, x = - \frac{3 ( 7 + 53 )}{2}

x, 2 x^{2} + 2 y^{2} + 2 z^{2} = 8 x - 16 z + 1

y, y^{2} = x^{3} - 5 x + 5

m^{2} + 18 m + 81 = 0

9 = 10 x - x^{2}

4 = x^{2} - 2 x - 3

What are the solutions to the equation 3x^2+63x+12=39 ?
The solutions to the equation 3x^2+63x+12=39 are x=(3(sqrt(53)-7))/2 ,x=-(3(7+sqrt(53)))/2
Find the zeros of 3x^2+63x+12=39
The zeros of 3x^2+63x+12=39 are x=(3(sqrt(53)-7))/2 ,x=-(3(7+sqrt(53)))/2