What are the solutions to the equation r^2+4r-60=0 ?

The solutions to the equation r^2+4r-60=0 are r=6,r=-10

Find the zeros of r^2+4r-60=0

The zeros of r^2+4r-60=0 are r=6,r=-10

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r^{2} + 4 r - 60 = 0

r = 6, r = - 10

Solution steps

r^{2} + 4 r - 60 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 60) = 16

r_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 4 + 16}{2 \cdot 1}, r_{2} = \frac{- 4 - 16}{2 \cdot 1}

r = \frac{- 4 + 16}{2 \cdot 1} : 6

r = \frac{- 4 - 16}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

r = 6, r = - 10

2 x^{2} - 2 x + 12 = 0

4 x^{2} + 30 x - 16 = 0

x, x^{2} + x^{2} = (x + y)^{2}

(- \frac{15}{4})^{2} + y^{2} = 1

4 x^{2} - 6 x - 11 = 0

What are the solutions to the equation r^2+4r-60=0 ?
The solutions to the equation r^2+4r-60=0 are r=6,r=-10
Find the zeros of r^2+4r-60=0
The zeros of r^2+4r-60=0 are r=6,r=-10