What are the solutions to the equation (x-9)(x+8)=0 ?

The solutions to the equation (x-9)(x+8)=0 are x=9,x=-8

Find the zeros of (x-9)(x+8)=0

The zeros of (x-9)(x+8)=0 are x=9,x=-8

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(x - 9) (x + 8) = 0

x = 9, x = - 8

Solution steps

(x - 9) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 8 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = 9, x = - 8

- 3 x^{2} + 6 x + 105 = 0

(4 - x)^{2} - 1 = 0

x, t^{3} = c (t^{2} - x^{2})

b, 6 c^{2} + 6 = c b^{2}

2 x^{2} - 7 = 113

What are the solutions to the equation (x-9)(x+8)=0 ?
The solutions to the equation (x-9)(x+8)=0 are x=9,x=-8
Find the zeros of (x-9)(x+8)=0
The zeros of (x-9)(x+8)=0 are x=9,x=-8