What are the solutions to the equation 7n^2=3-9n ?

The solutions to the equation 7n^2=3-9n are n=(-9+sqrt(165))/(14),n=(-9-sqrt(165))/(14)

Find the zeros of 7n^2=3-9n

The zeros of 7n^2=3-9n are n=(-9+sqrt(165))/(14),n=(-9-sqrt(165))/(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 n^{2} = 3 - 9 n

n = \frac{- 9 + 165}{14}, n = \frac{- 9 - 165}{14}

Decimal Notation

n = 0.27465 \dots, n = - 1.56037 \dots

Solution steps

7 n^{2} = 3 - 9 n

Move

9 n

to the left side

7 n^{2} + 9 n = 3

Move

3

to the left side

7 n^{2} + 9 n - 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

9^{2} - 4 \cdot 7 (- 3) = 165

n_{1, 2} = \frac{- 9 \pm 165}{2 \cdot 7}

Separate the solutions

n_{1} = \frac{- 9 + 165}{2 \cdot 7}, n_{2} = \frac{- 9 - 165}{2 \cdot 7}

n = \frac{- 9 + 165}{2 \cdot 7} : \frac{- 9 + 165}{14}

n = \frac{- 9 - 165}{2 \cdot 7} : \frac{- 9 - 165}{14}

The solutions to the quadratic equation are:

n = \frac{- 9 + 165}{14}, n = \frac{- 9 - 165}{14}

x^{2} + 1 - x = 0

x^{2} - (k + 2) x + 36 = 0

2 x^{2} = 1, 8 = 0

x^{2} - (a + 1) x + a = 0

a^{2} - a + 2 = 4

What are the solutions to the equation 7n^2=3-9n ?
The solutions to the equation 7n^2=3-9n are n=(-9+sqrt(165))/(14),n=(-9-sqrt(165))/(14)
Find the zeros of 7n^2=3-9n
The zeros of 7n^2=3-9n are n=(-9+sqrt(165))/(14),n=(-9-sqrt(165))/(14)