What are the solutions to the equation y^2+4=24 ?

The solutions to the equation y^2+4=24 are y=2sqrt(5),y=-2sqrt(5)

Find the zeros of y^2+4=24

The zeros of y^2+4=24 are y=2sqrt(5),y=-2sqrt(5)

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y^{2} + 4 = 24

y = 25, y = - 25

Decimal Notation

y = 4.47213 \dots, y = - 4.47213 \dots

Solution steps

y^{2} + 4 = 24

Move

4

to the right side

y^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 20, y = - 20

20 = 25

- 20 = - 25

y = 25, y = - 25

- 16 t^{2} + 24 t + 4 = 12

- 9 x^{2} + 6 x + 7 = 8

x + 0.2 = x^{2}

(8 x + 3) (x - 6) = 0

(x - 2)^{2} = \frac{1}{4 ( - \frac{2}{5} ) ^{0}}

What are the solutions to the equation y^2+4=24 ?
The solutions to the equation y^2+4=24 are y=2sqrt(5),y=-2sqrt(5)
Find the zeros of y^2+4=24
The zeros of y^2+4=24 are y=2sqrt(5),y=-2sqrt(5)