What are the solutions to the equation factor 20x^2+3x-2=0 ?

The solutions to the equation factor 20x^2+3x-2=0 are x= 1/4 ,x=-2/5

Find the zeros of factor 20x^2+3x-2=0

The zeros of factor 20x^2+3x-2=0 are x= 1/4 ,x=-2/5

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20 x^{2} + 3 x - 2 = 0

x = \frac{1}{4}, x = - \frac{2}{5}

Decimal Notation

x = 0.25, x = - 0.4

Solution steps

20 x^{2} + 3 x - 2 = 0

Factor

20 x^{2} + 3 x - 2 : (4 x - 1) (5 x + 2)

(4 x - 1) (5 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 1 = 0 or 5 x + 2 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

5 x + 2 = 0 : x = - \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{2}{5}

z^{2} + 3 z = 18

5. 4^{2} + x^{2} = 7. 8^{2}

x, x^{2} + y^{2} = 14 x y

(2 w - 3) w = 65

5 x^{2} + 25 x + 5 = 0

What are the solutions to the equation factor 20x^2+3x-2=0 ?
The solutions to the equation factor 20x^2+3x-2=0 are x= 1/4 ,x=-2/5
Find the zeros of factor 20x^2+3x-2=0
The zeros of factor 20x^2+3x-2=0 are x= 1/4 ,x=-2/5