What are the solutions to the equation solvefor x,x^2+y^2=14xy ?

The solutions to the equation solvefor x,x^2+y^2=14xy are x=(7+4sqrt(3))y,x=(7-4sqrt(3))y

Find the zeros of solvefor x,x^2+y^2=14xy

The zeros of solvefor x,x^2+y^2=14xy are x=(7+4sqrt(3))y,x=(7-4sqrt(3))y

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solve for

x, x^{2} + y^{2} = 14 x y

x = (7 + 43) y, x = (7 - 43) y

Solution steps

x^{2} + y^{2} = 14 x y

Move

14 x y

to the left side

x^{2} + y^{2} - 14 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 14 y x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 y ) \pm ( - 14 y ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

Simplify

(- 14 y)^{2} - 4 \cdot 1 \cdot y^{2} : 83 y

x_{1, 2} = \frac{- ( - 14 y ) \pm 8 3 y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 y ) + 8 3 y}{2 \cdot 1}, x_{2} = \frac{- ( - 14 y ) - 8 3 y}{2 \cdot 1}

x = \frac{- ( - 14 y ) + 8 3 y}{2 \cdot 1} : (7 + 43) y

x = \frac{- ( - 14 y ) - 8 3 y}{2 \cdot 1} : (7 - 43) y

The solutions to the quadratic equation are:

x = (7 + 43) y, x = (7 - 43) y

(2 w - 3) w = 65

5 x^{2} + 25 x + 5 = 0

3 x^{2} - 11 x - 10 = 0

(4 x + 5)^{2} = 64

- 2 (x + x^{2}) = 3

What are the solutions to the equation solvefor x,x^2+y^2=14xy ?
The solutions to the equation solvefor x,x^2+y^2=14xy are x=(7+4sqrt(3))y,x=(7-4sqrt(3))y
Find the zeros of solvefor x,x^2+y^2=14xy
The zeros of solvefor x,x^2+y^2=14xy are x=(7+4sqrt(3))y,x=(7-4sqrt(3))y