What are the solutions to the equation completesquare 5x^2+25x+5=0 ?

The solutions to the equation completesquare 5x^2+25x+5=0 are x=(sqrt(21)-5)/2 ,x=(-sqrt(21)-5)/2

Find the zeros of completesquare 5x^2+25x+5=0

The zeros of completesquare 5x^2+25x+5=0 are x=(sqrt(21)-5)/2 ,x=(-sqrt(21)-5)/2

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5 x^{2} + 25 x + 5 = 0

x = \frac{21 - 5}{2}, x = \frac{- 21 - 5}{2}

Decimal Notation

x = - 0.20871 \dots, x = - 4.79128 \dots

Solution steps

5 x^{2} + 25 x + 5 = 0

Move

5

to the right side

5 x^{2} + 25 x = - 5

Divide both sides by

5

\frac{5 x ^{2} + 25 x}{5} = \frac{- 5}{5}

x^{2} + 5 x = - 1

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{2})^{2} = \frac{21}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{2} = \frac{21}{4} : x = \frac{21 - 5}{2}

Solve

x + \frac{5}{2} = - \frac{21}{4} : x = \frac{- 21 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{21 - 5}{2}, x = \frac{- 21 - 5}{2}

3 x^{2} - 11 x - 10 = 0

(4 x + 5)^{2} = 64

- 2 (x + x^{2}) = 3

2 n^{2} + 36 = - 18 n

- 2 n^{2} + 2 n + 53 = - 7

What are the solutions to the equation completesquare 5x^2+25x+5=0 ?
The solutions to the equation completesquare 5x^2+25x+5=0 are x=(sqrt(21)-5)/2 ,x=(-sqrt(21)-5)/2
Find the zeros of completesquare 5x^2+25x+5=0
The zeros of completesquare 5x^2+25x+5=0 are x=(sqrt(21)-5)/2 ,x=(-sqrt(21)-5)/2