What are the solutions to the equation 3x^2-11x-10=0 ?

The solutions to the equation 3x^2-11x-10=0 are x=(11+sqrt(241))/6 ,x=(11-sqrt(241))/6

Find the zeros of 3x^2-11x-10=0

The zeros of 3x^2-11x-10=0 are x=(11+sqrt(241))/6 ,x=(11-sqrt(241))/6

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3 x^{2} - 11 x - 10 = 0

x = \frac{11 + 241}{6}, x = \frac{11 - 241}{6}

Decimal Notation

x = 4.42069 \dots, x = - 0.75402 \dots

Solution steps

3 x^{2} - 11 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 (- 10) = 241

x_{1, 2} = \frac{- ( - 11 ) \pm 241}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 241}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 241}{2 \cdot 3}

x = \frac{- ( - 11 ) + 241}{2 \cdot 3} : \frac{11 + 241}{6}

x = \frac{- ( - 11 ) - 241}{2 \cdot 3} : \frac{11 - 241}{6}

The solutions to the quadratic equation are:

x = \frac{11 + 241}{6}, x = \frac{11 - 241}{6}

(4 x + 5)^{2} = 64

- 2 (x + x^{2}) = 3

2 n^{2} + 36 = - 18 n

- 2 n^{2} + 2 n + 53 = - 7

2 x^{2} + 4 x + 6

What are the solutions to the equation 3x^2-11x-10=0 ?
The solutions to the equation 3x^2-11x-10=0 are x=(11+sqrt(241))/6 ,x=(11-sqrt(241))/6
Find the zeros of 3x^2-11x-10=0
The zeros of 3x^2-11x-10=0 are x=(11+sqrt(241))/6 ,x=(11-sqrt(241))/6