What are the solutions to the equation X^2-2X+5=0 ?

The solutions to the equation X^2-2X+5=0 are X=1+2i,X=1-2i

Find the zeros of X^2-2X+5=0

The zeros of X^2-2X+5=0 are X=1+2i,X=1-2i

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X^{2} - 2 X + 5 = 0

X = 1 + 2 i, X = 1 - 2 i

Solution steps

X^{2} - 2 X + 5 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 5 : 4 i

X_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 1}, X_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 1}

X = \frac{- ( - 2 ) + 4 i}{2 \cdot 1} : 1 + 2 i

X = \frac{- ( - 2 ) - 4 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

X = 1 + 2 i, X = 1 - 2 i

(1 + x)^{2} = 4

(x - 5) (x - 6) = 0

5 x^{2} = 10 x + 4

- 18.6 x^{2} + 497 x - 3010 = 0

x^{2} - 4 x + \frac{15}{4} = 0

What are the solutions to the equation X^2-2X+5=0 ?
The solutions to the equation X^2-2X+5=0 are X=1+2i,X=1-2i
Find the zeros of X^2-2X+5=0
The zeros of X^2-2X+5=0 are X=1+2i,X=1-2i