What are the solutions to the equation x^2-4x+15/4 =0 ?

The solutions to the equation x^2-4x+15/4 =0 are x= 5/2 ,x= 3/2

Find the zeros of x^2-4x+15/4 =0

The zeros of x^2-4x+15/4 =0 are x= 5/2 ,x= 3/2

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x^{2} - 4 x + \frac{15}{4} = 0

x = \frac{5}{2}, x = \frac{3}{2}

Decimal Notation

x = 2.5, x = 1.5

Solution steps

x^{2} - 4 x + \frac{15}{4} = 0

Multiply both sides by

4

4 x^{2} - 16 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 15 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 4}

x = \frac{- ( - 16 ) + 4}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 16 ) - 4}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{3}{2}

m^{2} - 12 m + 27 = 0

2 n^{2} + 9 n - 5 = 0

4 x (x - 2) - 3 x (x - 4) = - 3

c = 0.925 x^{2} - 4 x + 20

3 x + 3 = x^{2} + 2 x + 1

What are the solutions to the equation x^2-4x+15/4 =0 ?
The solutions to the equation x^2-4x+15/4 =0 are x= 5/2 ,x= 3/2
Find the zeros of x^2-4x+15/4 =0
The zeros of x^2-4x+15/4 =0 are x= 5/2 ,x= 3/2