What are the solutions to the equation (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5 ?

The solutions to the equation (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5 are d=sqrt(2),d=-sqrt(2)

Find the zeros of (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5

The zeros of (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5 are d=sqrt(2),d=-sqrt(2)

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\frac{8 d ^{2}}{5} + \frac{3 d ^{2}}{10} = 3 + \frac{2 d ^{2}}{5}

d = 2, d = - 2

Decimal Notation

d = 1.41421 \dots, d = - 1.41421 \dots

Solution steps

\frac{8 d ^{2}}{5} + \frac{3 d ^{2}}{10} = 3 + \frac{2 d ^{2}}{5}

Move

\frac{2 d ^{2}}{5}

to the left side

\frac{3 d ^{2}}{2} = 3

Multiply both sides by

2

3 d^{2} = 6

Divide both sides by

3

d^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 2, d = - 2

A (x) = x^{2} - 7 x + 2

C = x^{2} - 1200 x + 36400

4 x^{2} - 6 x + 6 = 0

0 = \frac{t ^{2} - t}{3}

8 X^{2} + 2 = 5

What are the solutions to the equation (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5 ?
The solutions to the equation (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5 are d=sqrt(2),d=-sqrt(2)
Find the zeros of (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5
The zeros of (8d^2)/5+(3d^2}{10}=3+\frac{2d^2)/5 are d=sqrt(2),d=-sqrt(2)