What are the solutions to the equation 2v^2+5v=7 ?

The solutions to the equation 2v^2+5v=7 are v=1,v=-7/2

Find the zeros of 2v^2+5v=7

The zeros of 2v^2+5v=7 are v=1,v=-7/2

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2 v^{2} + 5 v = 7

v = 1, v = - \frac{7}{2}

Decimal Notation

v = 1, v = - 3.5

Solution steps

2 v^{2} + 5 v = 7

Move

7

to the left side

2 v^{2} + 5 v - 7 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 7) = 9

v_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 5 + 9}{2 \cdot 2}, v_{2} = \frac{- 5 - 9}{2 \cdot 2}

v = \frac{- 5 + 9}{2 \cdot 2} : 1

v = \frac{- 5 - 9}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

v = 1, v = - \frac{7}{2}

2 x^{2} - 12 = - 15

(- x + 4)^{2} = 40

0.00029 = \frac{4 π \cdot 1 0 ^{- 7} \cdot x ^{2} \cdot 12.25}{4}

\frac{x ^{2}}{4} = 83

1 4^{2} = x^{2} + x^{2}

What are the solutions to the equation 2v^2+5v=7 ?
The solutions to the equation 2v^2+5v=7 are v=1,v=-7/2
Find the zeros of 2v^2+5v=7
The zeros of 2v^2+5v=7 are v=1,v=-7/2