What are the solutions to the equation -3(x+4)(x-7)=0 ?

The solutions to the equation -3(x+4)(x-7)=0 are x=-4,x=7

Find the zeros of -3(x+4)(x-7)=0

The zeros of -3(x+4)(x-7)=0 are x=-4,x=7

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- 3 (x + 4) (x - 7) = 0

x = - 4, x = 7

Solution steps

- 3 (x + 4) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 7 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 7 = 0 : x = 7

The solutions to the quadratic equation are:

x = - 4, x = 7

3 (x - 2)^{2} + 23 (x - 2) - 36 = 0

8 x^{2} + 6 x + 2 = 0

2 x (x - 2) = 6

x^{2} - 3 x - 13 = 0

r^{2} + 10 r + 24 = 0

What are the solutions to the equation -3(x+4)(x-7)=0 ?
The solutions to the equation -3(x+4)(x-7)=0 are x=-4,x=7
Find the zeros of -3(x+4)(x-7)=0
The zeros of -3(x+4)(x-7)=0 are x=-4,x=7