What are the solutions to the equation λ^2+14λ+49=0 ?

The solutions to the equation λ^2+14λ+49=0 are λ=-7

Find the zeros of λ^2+14λ+49=0

The zeros of λ^2+14λ+49=0 are λ=-7

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λ^{2} + 14 λ + 49 = 0

λ = - 7

Solution steps

λ^{2} + 14 λ + 49 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

λ_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

λ = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

λ = - 7

The solution to the quadratic equation is:

λ = - 7

4 y^{2} - 21 y - 18 = 0

x^{2} + 26 x + c

5 x^{2} - 15 x + 2 = 0

x^{2} + \frac{1}{2} x - 2 = 0

\frac{14 \cdot x ^{2}}{2} - 8.69 \cdot 2.4 \cdot (46.1 - x) = 0

What are the solutions to the equation λ^2+14λ+49=0 ?
The solutions to the equation λ^2+14λ+49=0 are λ=-7
Find the zeros of λ^2+14λ+49=0
The zeros of λ^2+14λ+49=0 are λ=-7