What are the solutions to the equation 4y^2-21y-18=0 ?

The solutions to the equation 4y^2-21y-18=0 are y=6,y=-3/4

Find the zeros of 4y^2-21y-18=0

The zeros of 4y^2-21y-18=0 are y=6,y=-3/4

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4 y^{2} - 21 y - 18 = 0

y = 6, y = - \frac{3}{4}

Decimal Notation

y = 6, y = - 0.75

Solution steps

4 y^{2} - 21 y - 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 4 ( - 18 )}{2 \cdot 4}

(- 21)^{2} - 4 \cdot 4 (- 18) = 27

y_{1, 2} = \frac{- ( - 21 ) \pm 27}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 21 ) + 27}{2 \cdot 4}, y_{2} = \frac{- ( - 21 ) - 27}{2 \cdot 4}

y = \frac{- ( - 21 ) + 27}{2 \cdot 4} : 6

y = \frac{- ( - 21 ) - 27}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

y = 6, y = - \frac{3}{4}

x^{2} + 26 x + c

5 x^{2} - 15 x + 2 = 0

x^{2} + \frac{1}{2} x - 2 = 0

\frac{14 \cdot x ^{2}}{2} - 8.69 \cdot 2.4 \cdot (46.1 - x) = 0

x^{2} - \frac{16}{3} x + 2 = 0

What are the solutions to the equation 4y^2-21y-18=0 ?
The solutions to the equation 4y^2-21y-18=0 are y=6,y=-3/4
Find the zeros of 4y^2-21y-18=0
The zeros of 4y^2-21y-18=0 are y=6,y=-3/4