What are the solutions to the equation 2x(x+2)=20 ?

The solutions to the equation 2x(x+2)=20 are x=-1+sqrt(11),x=-1-sqrt(11)

Find the zeros of 2x(x+2)=20

The zeros of 2x(x+2)=20 are x=-1+sqrt(11),x=-1-sqrt(11)

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2 x (x + 2) = 20

x = - 1 + 11, x = - 1 - 11

Decimal Notation

x = 2.31662 \dots, x = - 4.31662 \dots

Solution steps

2 x (x + 2) = 20

Expand

2 x (x + 2) : 2 x^{2} + 4 x

2 x^{2} + 4 x = 20

Move

20

to the left side

2 x^{2} + 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 20) = 411

x_{1, 2} = \frac{- 4 \pm 4 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 11}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 11}{2 \cdot 2}

x = \frac{- 4 + 4 11}{2 \cdot 2} : - 1 + 11

x = \frac{- 4 - 4 11}{2 \cdot 2} : - 1 - 11

The solutions to the quadratic equation are:

x = - 1 + 11, x = - 1 - 11

\frac{x ^{2}}{6} + \frac{5 x}{6} - 1 = 0

x, (x - 1)^{2} + (y - 6)^{2} + z^{2} = 21

8 - 0.5 x^{2} = x + 6.5

- 49 = 2 (36.75) - 4.9 x^{2}

10 = 15 + 22 t - 5 t^{2}

What are the solutions to the equation 2x(x+2)=20 ?
The solutions to the equation 2x(x+2)=20 are x=-1+sqrt(11),x=-1-sqrt(11)
Find the zeros of 2x(x+2)=20
The zeros of 2x(x+2)=20 are x=-1+sqrt(11),x=-1-sqrt(11)