What are the solutions to the equation w^2=15w ?

The solutions to the equation w^2=15w are w=15,w=0

Find the zeros of w^2=15w

The zeros of w^2=15w are w=15,w=0

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w^{2} = 15 w

w = 15, w = 0

Solution steps

w^{2} = 15 w

Move

15 w

to the left side

w^{2} - 15 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 0 = 15

w_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 1}, w_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 1}

w = \frac{- ( - 15 ) + 15}{2 \cdot 1} : 15

w = \frac{- ( - 15 ) - 15}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

w = 15, w = 0

n^{2} + 1 = 0

x^{2} + 3 x + x = 0

x, x^{2} y + 2 y = x + 4

\frac{3 x ^{2}}{4} = \frac{x}{5} + 2

a, (a + b + c) (1 + ab + a c + b c) = 32

What are the solutions to the equation w^2=15w ?
The solutions to the equation w^2=15w are w=15,w=0
Find the zeros of w^2=15w
The zeros of w^2=15w are w=15,w=0