What are the solutions to the equation u^2-2u-1=0 ?

The solutions to the equation u^2-2u-1=0 are u=1+sqrt(2),u=1-sqrt(2)

Find the zeros of u^2-2u-1=0

The zeros of u^2-2u-1=0 are u=1+sqrt(2),u=1-sqrt(2)

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u^{2} - 2 u - 1 = 0

u = 1 + 2, u = 1 - 2

Decimal Notation

u = 2.41421 \dots, u = - 0.41421 \dots

Solution steps

u^{2} - 2 u - 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

u_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, u_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

u = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

u = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

u = 1 + 2, u = 1 - 2

4 - 3 x - x^{2} = 0

y, x y^{2} + x^{2} y + x^{4} = 2

3 x^{2} - 9 x + 20 = 0

5 x^{2} - 12 = 168

x, c x^{2} + x + y^{2} = 0

What are the solutions to the equation u^2-2u-1=0 ?
The solutions to the equation u^2-2u-1=0 are u=1+sqrt(2),u=1-sqrt(2)
Find the zeros of u^2-2u-1=0
The zeros of u^2-2u-1=0 are u=1+sqrt(2),u=1-sqrt(2)