What are the solutions to the equation 4-3x-x^2=0 ?

The solutions to the equation 4-3x-x^2=0 are x=-4,x=1

Find the zeros of 4-3x-x^2=0

The zeros of 4-3x-x^2=0 are x=-4,x=1

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4 - 3 x - x^{2} = 0

x = - 4, x = 1

Solution steps

4 - 3 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 4 = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 5}{2 ( - 1 )} : - 4

x = \frac{- ( - 3 ) - 5}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 4, x = 1

y, x y^{2} + x^{2} y + x^{4} = 2

3 x^{2} - 9 x + 20 = 0

5 x^{2} - 12 = 168

x, c x^{2} + x + y^{2} = 0

q^{2} - 12 q + 40 = 40

What are the solutions to the equation 4-3x-x^2=0 ?
The solutions to the equation 4-3x-x^2=0 are x=-4,x=1
Find the zeros of 4-3x-x^2=0
The zeros of 4-3x-x^2=0 are x=-4,x=1