What are the solutions to the equation 1-8x=-16x^2 ?

The solutions to the equation 1-8x=-16x^2 are x= 1/4

Find the zeros of 1-8x=-16x^2

The zeros of 1-8x=-16x^2 are x= 1/4

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1 - 8 x = - 16 x^{2}

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

1 - 8 x = - 16 x^{2}

Switch sides

- 16 x^{2} = 1 - 8 x

Move

8 x

to the left side

- 16 x^{2} + 8 x = 1

Move

1

to the left side

- 16 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 16 ) ( - 1 )}{2 ( - 16 )}

8^{2} - 4 (- 16) (- 1) = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 ( - 16 )}

x = \frac{- 8}{2 ( - 16 )}

\frac{- 8}{2 ( - 16 )} = \frac{1}{4}

x = \frac{1}{4}

The solution to the quadratic equation is:

x = \frac{1}{4}

5 = 12 (1 - \frac{x}{- 3.5})^{2}

3 x^{2} - 8 x = - 3

2 x^{2} - 3 x + 1 = 0

4 k^{2} + 3 = - 13 k

y, c y^{2} = x^{2} (x - a)

What are the solutions to the equation 1-8x=-16x^2 ?
The solutions to the equation 1-8x=-16x^2 are x= 1/4
Find the zeros of 1-8x=-16x^2
The zeros of 1-8x=-16x^2 are x= 1/4