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Popular >

t^2-13t+36=0

Solution

t^{2} - 13 t + 36 = 0

Solution

t = 9, t = 4

Solution steps

t^{2} - 13 t + 36 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

t_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, t_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

t = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

t = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

t = 9, t = 4

Popular Examples

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q, - 0.3 q^{2} + 36 q = - 3 q - 100

1/8 x^2+2x+16=0

\frac{1}{8} x^{2} + 2 x + 16 = 0

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x, 3 x^{2} - 6 y^{2} + 3 x y + x + 2 y = 0

h^2+80^2=(2h+11)^2

h^{2} + 8 0^{2} = (2 h + 11)^{2}

Frequently Asked Questions (FAQ)

What are the solutions to the equation t^2-13t+36=0 ?
The solutions to the equation t^2-13t+36=0 are t=9,t=4
Find the zeros of t^2-13t+36=0
The zeros of t^2-13t+36=0 are t=9,t=4