What are the solutions to the equation -z^2+3z-4=0 ?

The solutions to the equation -z^2+3z-4=0 are z= 3/2-i(sqrt(7))/2 ,z= 3/2+i(sqrt(7))/2

Find the zeros of -z^2+3z-4=0

The zeros of -z^2+3z-4=0 are z= 3/2-i(sqrt(7))/2 ,z= 3/2+i(sqrt(7))/2

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- z^{2} + 3 z - 4 = 0

z = \frac{3}{2} - i \frac{7}{2}, z = \frac{3}{2} + i \frac{7}{2}

Solution steps

- z^{2} + 3 z - 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 4) : 7 i

z_{1, 2} = \frac{- 3 \pm 7 i}{2 ( - 1 )}

Separate the solutions

z_{1} = \frac{- 3 + 7 i}{2 ( - 1 )}, z_{2} = \frac{- 3 - 7 i}{2 ( - 1 )}

z = \frac{- 3 + 7 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{7}{2}

z = \frac{- 3 - 7 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

z = \frac{3}{2} - i \frac{7}{2}, z = \frac{3}{2} + i \frac{7}{2}

x^{2} - 12 x + 22 = 0

3 x^{2} - 8 = - 200

- 3 x^{2} + 36 x - 96 = 0

2 x^{2} + (2 x - 8)^{2} - 5 x (2 x - 8) + 32 = 0

4 b^{2} - 8 b - 5 = 0

What are the solutions to the equation -z^2+3z-4=0 ?
The solutions to the equation -z^2+3z-4=0 are z= 3/2-i(sqrt(7))/2 ,z= 3/2+i(sqrt(7))/2
Find the zeros of -z^2+3z-4=0
The zeros of -z^2+3z-4=0 are z= 3/2-i(sqrt(7))/2 ,z= 3/2+i(sqrt(7))/2