What are the solutions to the equation completesquare x^2-12x+22=0 ?

The solutions to the equation completesquare x^2-12x+22=0 are x=sqrt(14)+6,x=-sqrt(14)+6

Find the zeros of completesquare x^2-12x+22=0

The zeros of completesquare x^2-12x+22=0 are x=sqrt(14)+6,x=-sqrt(14)+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 12 x + 22 = 0

x = 14 + 6, x = - 14 + 6

Decimal Notation

x = 9.74165 \dots, x = 2.25834 \dots

Solution steps

x^{2} - 12 x + 22 = 0

Move

22

to the right side

x^{2} - 12 x = - 22

Rewrite in the form

(x + a)^{2} = b

(x - 6)^{2} = 14

For

the solutions are

f (x) = a, - a

Solve

x - 6 = 14 : x = 14 + 6

Solve

x - 6 = - 14 : x = - 14 + 6

The solutions to the quadratic equation are:

x = 14 + 6, x = - 14 + 6

3 x^{2} - 8 = - 200

- 3 x^{2} + 36 x - 96 = 0

2 x^{2} + (2 x - 8)^{2} - 5 x (2 x - 8) + 32 = 0

4 b^{2} - 8 b - 5 = 0

x^{2} - 20 x = 4

What are the solutions to the equation completesquare x^2-12x+22=0 ?
The solutions to the equation completesquare x^2-12x+22=0 are x=sqrt(14)+6,x=-sqrt(14)+6
Find the zeros of completesquare x^2-12x+22=0
The zeros of completesquare x^2-12x+22=0 are x=sqrt(14)+6,x=-sqrt(14)+6