What are the solutions to the equation -3x^2+36x-96=0 ?

The solutions to the equation -3x^2+36x-96=0 are x=4,x=8

Find the zeros of -3x^2+36x-96=0

The zeros of -3x^2+36x-96=0 are x=4,x=8

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- 3 x^{2} + 36 x - 96 = 0

x = 4, x = 8

Solution steps

- 3 x^{2} + 36 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 3 ) ( - 96 )}{2 ( - 3 )}

3 6^{2} - 4 (- 3) (- 96) = 12

x_{1, 2} = \frac{- 36 \pm 12}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 36 + 12}{2 ( - 3 )}, x_{2} = \frac{- 36 - 12}{2 ( - 3 )}

x = \frac{- 36 + 12}{2 ( - 3 )} : 4

x = \frac{- 36 - 12}{2 ( - 3 )} : 8

The solutions to the quadratic equation are:

x = 4, x = 8

2 x^{2} + (2 x - 8)^{2} - 5 x (2 x - 8) + 32 = 0

4 b^{2} - 8 b - 5 = 0

x^{2} - 20 x = 4

646.8 - 205.6 x + 12 x^{2} = 0

(x + 2) (x - 3) = x - 6

What are the solutions to the equation -3x^2+36x-96=0 ?
The solutions to the equation -3x^2+36x-96=0 are x=4,x=8
Find the zeros of -3x^2+36x-96=0
The zeros of -3x^2+36x-96=0 are x=4,x=8