What are the solutions to the equation x^2-20x=4 ?

The solutions to the equation x^2-20x=4 are x=2(5+sqrt(26)),x=2(5-sqrt(26))

Find the zeros of x^2-20x=4

The zeros of x^2-20x=4 are x=2(5+sqrt(26)),x=2(5-sqrt(26))

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x^{2} - 20 x = 4

x = 2 (5 + 26), x = 2 (5 - 26)

Decimal Notation

x = 20.19803 \dots, x = - 0.19803 \dots

Solution steps

x^{2} - 20 x = 4

Move

4

to the left side

x^{2} - 20 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 4) = 426

x_{1, 2} = \frac{- ( - 20 ) \pm 4 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 26}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 4 26}{2 \cdot 1}

x = \frac{- ( - 20 ) + 4 26}{2 \cdot 1} : 2 (5 + 26)

x = \frac{- ( - 20 ) - 4 26}{2 \cdot 1} : 2 (5 - 26)

The solutions to the quadratic equation are:

x = 2 (5 + 26), x = 2 (5 - 26)

646.8 - 205.6 x + 12 x^{2} = 0

(x + 2) (x - 3) = x - 6

x^{2} - 12 x + 21 = 0

4 m^{2} + m = 5

0 = c^{1} (\frac{1}{2}) + c^{2} (\frac{3}{2})

What are the solutions to the equation x^2-20x=4 ?
The solutions to the equation x^2-20x=4 are x=2(5+sqrt(26)),x=2(5-sqrt(26))
Find the zeros of x^2-20x=4
The zeros of x^2-20x=4 are x=2(5+sqrt(26)),x=2(5-sqrt(26))