What are the solutions to the equation (x+2)(x-3)=x-6 ?

The solutions to the equation (x+2)(x-3)=x-6 are x=2,x=0

Find the zeros of (x+2)(x-3)=x-6

The zeros of (x+2)(x-3)=x-6 are x=2,x=0

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(x + 2) (x - 3) = x - 6

x = 2, x = 0

Solution steps

(x + 2) (x - 3) = x - 6

Expand

(x + 2) (x - 3) : x^{2} - x - 6

x^{2} - x - 6 = x - 6

Move

6

to the left side

x^{2} - x = x

Move

x

to the left side

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

x^{2} - 12 x + 21 = 0

4 m^{2} + m = 5

0 = c^{1} (\frac{1}{2}) + c^{2} (\frac{3}{2})

- 6 y^{2} - 9 y + 1 = 0

8 x^{2} - 22 x + 5 = 0

What are the solutions to the equation (x+2)(x-3)=x-6 ?
The solutions to the equation (x+2)(x-3)=x-6 are x=2,x=0
Find the zeros of (x+2)(x-3)=x-6
The zeros of (x+2)(x-3)=x-6 are x=2,x=0