What are the solutions to the equation 0=-0.25x^2+4x-9 ?

The solutions to the equation 0=-0.25x^2+4x-9 are x=2(4-sqrt(7)),x=2(4+sqrt(7))

Find the zeros of 0=-0.25x^2+4x-9

The zeros of 0=-0.25x^2+4x-9 are x=2(4-sqrt(7)),x=2(4+sqrt(7))

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0 = - 0.25 x^{2} + 4 x - 9

x = 2 (4 - 7), x = 2 (4 + 7)

Decimal Notation

x = 2.70849 \dots, x = 13.29150 \dots

Solution steps

0 = - 0.25 x^{2} + 4 x - 9

Multiply both sides by

100

0 = - 25 x^{2} + 400 x - 900

Switch sides

- 25 x^{2} + 400 x - 900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 25 ) ( - 900 )}{2 ( - 25 )}

40 0^{2} - 4 (- 25) (- 900) = 1007

x_{1, 2} = \frac{- 400 \pm 100 7}{2 ( - 25 )}

Separate the solutions

x_{1} = \frac{- 400 + 100 7}{2 ( - 25 )}, x_{2} = \frac{- 400 - 100 7}{2 ( - 25 )}

x = \frac{- 400 + 100 7}{2 ( - 25 )} : 2 (4 - 7)

x = \frac{- 400 - 100 7}{2 ( - 25 )} : 2 (4 + 7)

The solutions to the quadratic equation are:

x = 2 (4 - 7), x = 2 (4 + 7)

- 0.01 x^{2} - 0.1 x + 6 = 4

4 x^{2} - 9 = 16

4 x (x + 6) - x^{2} = 5 x^{2}

25 x^{2} - 100 x = 0

7 x^{2} + 41 x - 6 = 0

What are the solutions to the equation 0=-0.25x^2+4x-9 ?
The solutions to the equation 0=-0.25x^2+4x-9 are x=2(4-sqrt(7)),x=2(4+sqrt(7))
Find the zeros of 0=-0.25x^2+4x-9
The zeros of 0=-0.25x^2+4x-9 are x=2(4-sqrt(7)),x=2(4+sqrt(7))