What are the solutions to the equation 0=-x^2+4x-2 ?

The solutions to the equation 0=-x^2+4x-2 are x=2-sqrt(2),x=2+sqrt(2)

Find the zeros of 0=-x^2+4x-2

The zeros of 0=-x^2+4x-2 are x=2-sqrt(2),x=2+sqrt(2)

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0 = - x^{2} + 4 x - 2

x = 2 - 2, x = 2 + 2

Decimal Notation

x = 0.58578 \dots, x = 3.41421 \dots

Solution steps

0 = - x^{2} + 4 x - 2

Switch sides

- x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 2) = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 2}{2 ( - 1 )}

x = \frac{- 4 + 2 2}{2 ( - 1 )} : 2 - 2

x = \frac{- 4 - 2 2}{2 ( - 1 )} : 2 + 2

The solutions to the quadratic equation are:

x = 2 - 2, x = 2 + 2

227 - 0.25 x^{2} = 2 + 2 x^{2}

32 x - 4 = 4 x^{2} + 60

- x^{2} + 10 x + 11 = 0

0 = - x^{2} + 4 x + 3

3 x^{2} + 2 x

What are the solutions to the equation 0=-x^2+4x-2 ?
The solutions to the equation 0=-x^2+4x-2 are x=2-sqrt(2),x=2+sqrt(2)
Find the zeros of 0=-x^2+4x-2
The zeros of 0=-x^2+4x-2 are x=2-sqrt(2),x=2+sqrt(2)