What are the solutions to the equation (x+12)^2=97 ?

The solutions to the equation (x+12)^2=97 are x=sqrt(97)-12,x=-sqrt(97)-12

Find the zeros of (x+12)^2=97

The zeros of (x+12)^2=97 are x=sqrt(97)-12,x=-sqrt(97)-12

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(x + 12)^{2} = 97

x = 97 - 12, x = - 97 - 12

Decimal Notation

x = - 2.15114 \dots, x = - 21.84885 \dots

Solution steps

(x + 12)^{2} = 97

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 12 = 97 : x = 97 - 12

Solve

x + 12 = - 97 : x = - 97 - 12

The solutions to the quadratic equation are:

x = 97 - 12, x = - 97 - 12

12 m^{2} + 20 m = 0

- 49 x^{2} + 144 = 0

x, 2 x^{2} - y^{2} = 0

s^{2} + s - 2 + 10 = 0

7 x^{2} - 8 x^{2} - 21 x + 24 = 0

What are the solutions to the equation (x+12)^2=97 ?
The solutions to the equation (x+12)^2=97 are x=sqrt(97)-12,x=-sqrt(97)-12
Find the zeros of (x+12)^2=97
The zeros of (x+12)^2=97 are x=sqrt(97)-12,x=-sqrt(97)-12