What are the solutions to the equation x^2+105x-2500=0 ?

The solutions to the equation x^2+105x-2500=0 are x=20,x=-125

Find the zeros of x^2+105x-2500=0

The zeros of x^2+105x-2500=0 are x=20,x=-125

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x^{2} + 105 x - 2500 = 0

x = 20, x = - 125

Solution steps

x^{2} + 105 x - 2500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 105 \pm 10 5 ^{2} - 4 \cdot 1 \cdot ( - 2500 )}{2 \cdot 1}

10 5^{2} - 4 \cdot 1 \cdot (- 2500) = 145

x_{1, 2} = \frac{- 105 \pm 145}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 105 + 145}{2 \cdot 1}, x_{2} = \frac{- 105 - 145}{2 \cdot 1}

x = \frac{- 105 + 145}{2 \cdot 1} : 20

x = \frac{- 105 - 145}{2 \cdot 1} : - 125

The solutions to the quadratic equation are:

x = 20, x = - 125

x^{2} = 15 + 2 x

r^{2} + 120 r + 10000 = 0

x (x + 3) - 5 (2 x - 4) = 2 x

- 3 x^{2} + 6 x - 24 = 0

100 x^{2} = 25

What are the solutions to the equation x^2+105x-2500=0 ?
The solutions to the equation x^2+105x-2500=0 are x=20,x=-125
Find the zeros of x^2+105x-2500=0
The zeros of x^2+105x-2500=0 are x=20,x=-125