What are the solutions to the equation -3x^2+6x-24=0 ?

The solutions to the equation -3x^2+6x-24=0 are x=1-sqrt(7)i,x=1+sqrt(7)i

Find the zeros of -3x^2+6x-24=0

The zeros of -3x^2+6x-24=0 are x=1-sqrt(7)i,x=1+sqrt(7)i

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- 3 x^{2} + 6 x - 24 = 0

x = 1 - 7 i, x = 1 + 7 i

Solution steps

- 3 x^{2} + 6 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 24 )}{2 ( - 3 )}

Simplify

6^{2} - 4 (- 3) (- 24) : 67 i

x_{1, 2} = \frac{- 6 \pm 6 7 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 7 i}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6 7 i}{2 ( - 3 )}

x = \frac{- 6 + 6 7 i}{2 ( - 3 )} : 1 - 7 i

x = \frac{- 6 - 6 7 i}{2 ( - 3 )} : 1 + 7 i

The solutions to the quadratic equation are:

x = 1 - 7 i, x = 1 + 7 i

100 x^{2} = 25

a^{2} + 2 a - 2 = 0

- \frac{1}{4} x^{2} + 4 x - 6 = 0

5 x^{2} - 15 x - 10 = 20

- 6 x^{2} + 26 x + 20 = 0

What are the solutions to the equation -3x^2+6x-24=0 ?
The solutions to the equation -3x^2+6x-24=0 are x=1-sqrt(7)i,x=1+sqrt(7)i
Find the zeros of -3x^2+6x-24=0
The zeros of -3x^2+6x-24=0 are x=1-sqrt(7)i,x=1+sqrt(7)i