What are the solutions to the equation r^2+120r+10000=0 ?

The solutions to the equation r^2+120r+10000=0 are r=-60+80i,r=-60-80i

Find the zeros of r^2+120r+10000=0

The zeros of r^2+120r+10000=0 are r=-60+80i,r=-60-80i

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r^{2} + 120 r + 10000 = 0

r = - 60 + 80 i, r = - 60 - 80 i

Solution steps

r^{2} + 120 r + 10000 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 1 \cdot 10000}{2 \cdot 1}

Simplify

12 0^{2} - 4 \cdot 1 \cdot 10000 : 160 i

r_{1, 2} = \frac{- 120 \pm 160 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 120 + 160 i}{2 \cdot 1}, r_{2} = \frac{- 120 - 160 i}{2 \cdot 1}

r = \frac{- 120 + 160 i}{2 \cdot 1} : - 60 + 80 i

r = \frac{- 120 - 160 i}{2 \cdot 1} : - 60 - 80 i

The solutions to the quadratic equation are:

r = - 60 + 80 i, r = - 60 - 80 i

x (x + 3) - 5 (2 x - 4) = 2 x

- 3 x^{2} + 6 x - 24 = 0

100 x^{2} = 25

a^{2} + 2 a - 2 = 0

- \frac{1}{4} x^{2} + 4 x - 6 = 0

What are the solutions to the equation r^2+120r+10000=0 ?
The solutions to the equation r^2+120r+10000=0 are r=-60+80i,r=-60-80i
Find the zeros of r^2+120r+10000=0
The zeros of r^2+120r+10000=0 are r=-60+80i,r=-60-80i