What are the solutions to the equation 4u^2+8u=-1 ?

The solutions to the equation 4u^2+8u=-1 are u=(-2+sqrt(3))/2 ,u=-(2+sqrt(3))/2

Find the zeros of 4u^2+8u=-1

The zeros of 4u^2+8u=-1 are u=(-2+sqrt(3))/2 ,u=-(2+sqrt(3))/2

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4 u^{2} + 8 u = - 1

u = \frac{- 2 + 3}{2}, u = - \frac{2 + 3}{2}

Decimal Notation

u = - 0.13397 \dots, u = - 1.86602 \dots

Solution steps

4 u^{2} + 8 u = - 1

Move

1

to the left side

4 u^{2} + 8 u + 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 1 = 43

u_{1, 2} = \frac{- 8 \pm 4 3}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- 8 + 4 3}{2 \cdot 4}, u_{2} = \frac{- 8 - 4 3}{2 \cdot 4}

u = \frac{- 8 + 4 3}{2 \cdot 4} : \frac{- 2 + 3}{2}

u = \frac{- 8 - 4 3}{2 \cdot 4} : - \frac{2 + 3}{2}

The solutions to the quadratic equation are:

u = \frac{- 2 + 3}{2}, u = - \frac{2 + 3}{2}

m^{2} - 14 = 0

x^{2} + 999 x - 1000001000 = 0

\frac{x ^{2}}{10} + 5 = 20 - \frac{x}{2}

- 0.2 x^{2} + 20 = 0

x^{2} - 4 = - 2 x + 4

What are the solutions to the equation 4u^2+8u=-1 ?
The solutions to the equation 4u^2+8u=-1 are u=(-2+sqrt(3))/2 ,u=-(2+sqrt(3))/2
Find the zeros of 4u^2+8u=-1
The zeros of 4u^2+8u=-1 are u=(-2+sqrt(3))/2 ,u=-(2+sqrt(3))/2