What are the solutions to the equation x^2+(7-26/3)^2=64 ?

The solutions to the equation x^2+(7-26/3)^2=64 are x=(sqrt(551))/3 ,x=-(sqrt(551))/3

Find the zeros of x^2+(7-26/3)^2=64

The zeros of x^2+(7-26/3)^2=64 are x=(sqrt(551))/3 ,x=-(sqrt(551))/3

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x^{2} + (7 - \frac{26}{3})^{2} = 64

x = \frac{551}{3}, x = - \frac{551}{3}

Decimal Notation

x = 7.82446 \dots, x = - 7.82446 \dots

Solution steps

x^{2} + (7 - \frac{26}{3})^{2} = 64

Move

(7 - \frac{26}{3})^{2}

to the right side

x^{2} = 64 - (7 - \frac{26}{3})^{2}

Simplify

64 - (7 - \frac{26}{3})^{2} : \frac{551}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{551}{9}, x = - \frac{551}{9}

\frac{551}{9} = \frac{551}{3}

- \frac{551}{9} = - \frac{551}{3}

x = \frac{551}{3}, x = - \frac{551}{3}

2 m^{2} - m^{2} - 18 m + 9 = 0

x^{2} + x + \frac{1}{4} = 0

(x + 3) (2 x - 1) = 9

- 20 y - 25 = 4 y^{2}

h^{2} - 3 h - 6 = 0

What are the solutions to the equation x^2+(7-26/3)^2=64 ?
The solutions to the equation x^2+(7-26/3)^2=64 are x=(sqrt(551))/3 ,x=-(sqrt(551))/3
Find the zeros of x^2+(7-26/3)^2=64
The zeros of x^2+(7-26/3)^2=64 are x=(sqrt(551))/3 ,x=-(sqrt(551))/3