What are the solutions to the equation (x+3)(2x-1)=9 ?

The solutions to the equation (x+3)(2x-1)=9 are x= 3/2 ,x=-4

Find the zeros of (x+3)(2x-1)=9

The zeros of (x+3)(2x-1)=9 are x= 3/2 ,x=-4

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(x + 3) (2 x - 1) = 9

x = \frac{3}{2}, x = - 4

Decimal Notation

x = 1.5, x = - 4

Solution steps

(x + 3) (2 x - 1) = 9

Expand

(x + 3) (2 x - 1) : 2 x^{2} + 5 x - 3

2 x^{2} + 5 x - 3 = 9

Move

9

to the left side

2 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 2}, x_{2} = \frac{- 5 - 11}{2 \cdot 2}

x = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 4

- 20 y - 25 = 4 y^{2}

h^{2} - 3 h - 6 = 0

k^{2} + 6 k + 8 = 0

- 10 x^{2} + 1760 x - 5000 = 0

4 x^{2} = 6 x - 2

What are the solutions to the equation (x+3)(2x-1)=9 ?
The solutions to the equation (x+3)(2x-1)=9 are x= 3/2 ,x=-4
Find the zeros of (x+3)(2x-1)=9
The zeros of (x+3)(2x-1)=9 are x= 3/2 ,x=-4