What are the solutions to the equation h^2-3h-6=0 ?

The solutions to the equation h^2-3h-6=0 are h=(3+sqrt(33))/2 ,h=(3-sqrt(33))/2

Find the zeros of h^2-3h-6=0

The zeros of h^2-3h-6=0 are h=(3+sqrt(33))/2 ,h=(3-sqrt(33))/2

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h^{2} - 3 h - 6 = 0

h = \frac{3 + 33}{2}, h = \frac{3 - 33}{2}

Decimal Notation

h = 4.37228 \dots, h = - 1.37228 \dots

Solution steps

h^{2} - 3 h - 6 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 6) = 33

h_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 1}, h_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 1}

h = \frac{- ( - 3 ) + 33}{2 \cdot 1} : \frac{3 + 33}{2}

h = \frac{- ( - 3 ) - 33}{2 \cdot 1} : \frac{3 - 33}{2}

The solutions to the quadratic equation are:

h = \frac{3 + 33}{2}, h = \frac{3 - 33}{2}

k^{2} + 6 k + 8 = 0

- 10 x^{2} + 1760 x - 5000 = 0

4 x^{2} = 6 x - 2

- x^{2} + 2 x = 6

5 x^{2} - 16 x + 16 = 0

What are the solutions to the equation h^2-3h-6=0 ?
The solutions to the equation h^2-3h-6=0 are h=(3+sqrt(33))/2 ,h=(3-sqrt(33))/2
Find the zeros of h^2-3h-6=0
The zeros of h^2-3h-6=0 are h=(3+sqrt(33))/2 ,h=(3-sqrt(33))/2