What are the solutions to the equation x^2-3x+2=2x-2 ?

The solutions to the equation x^2-3x+2=2x-2 are x=4,x=1

Find the zeros of x^2-3x+2=2x-2

The zeros of x^2-3x+2=2x-2 are x=4,x=1

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x^{2} - 3 x + 2 = 2 x - 2

x = 4, x = 1

Solution steps

x^{2} - 3 x + 2 = 2 x - 2

Move

2

to the left side

x^{2} - 3 x + 4 = 2 x

Move

2 x

to the left side

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

3 u^{2} - 12 u = 0

x^{2} + 18 x - 9 = 0

3 x^{2} - 12 x + 5 = 0

(4 k + 5) (k + 7) = 0

x, x^{2} + y^{2} - x + y + 1 = 0

What are the solutions to the equation x^2-3x+2=2x-2 ?
The solutions to the equation x^2-3x+2=2x-2 are x=4,x=1
Find the zeros of x^2-3x+2=2x-2
The zeros of x^2-3x+2=2x-2 are x=4,x=1